Skip to content
  • Start free trial
An original census record

Start a free trial to view

Get access to the original record, as well as a map showing the local area at the time

Household of Richard Fenemore (born 1846, Oxfordshire)

1881 England, Wales & Scotland Census in Witney, Oxfordshire, England

Richard Fenemore and 6 other people are on this record


Get access to the original record, as well as a map showing the local area at the time

Richard Fenemore's household

Male

Richard

Fenemore

Head
Female

Betsey

Fenemore

Wife
Female

Hannah

Fenemore

Daughter
Male

Edgar Owen

Fenemore

Son
Male

Henry Richard

Fenemore

Son
Female

Ellen J

Fenemore

Daughter
Female

?

Fenemore

Daughter
First name(s) Richard
Last name Fenemore
Relationship Head
Marital status Married
Age 35
Birth year 1846
Birth place Witney, Oxfordshire, England

Household members (7 people)

First name(s)

Last name

Relationship

Marital status

Age

Birth year

Birth place

Full record

Richard

Fenemore

Head

Married

35

1846

Witney, Oxfordshire, England

Betsey

Fenemore

Wife

Married

39

1842

Witney, Oxfordshire, England

Hannah

Fenemore

Daughter

Single

11

1870

Witney, Oxfordshire, England

Edgar Owen

Fenemore

Son

Single

9

1872

Witney, Oxfordshire, England

Henry Richard

Fenemore

Son

Single

6

1875

Witney, Oxfordshire, England

Ellen J

Fenemore

Daughter

Single

2

1879

Witney, Oxfordshire, England

?

Fenemore

Daughter

Single

0

1881

Witney, Oxfordshire, England

Explore Findmypast's newspaper collections

Explore the 1881 Census and millions of historical records for free with Findmypast. Find out more about the household of Richard Fenemore in Witney in 1881, and follow the Fenemore family through time in other national records, newspapers and more.

We've found family trees for Richard Fenemore

We’ve found Richard Fenemore in 13 family trees. Find out more about Richard Fenemore's household and view the Fenemore family in family trees created by Findmypast members.

Not who you're looking for?