Skip to content
  • Start free trial
An original census record

Start a free trial to view

Get access to the original record, as well as a map showing the local area at the time

Household of James Skinner (born 1835)

1881 England, Wales & Scotland Census in Kensington, London,Middlesex, England

James Skinner and 7 other people are on this record


Get access to the original record, as well as a map showing the local area at the time

James Skinner's household

Male

James

Skinner

Head
Female

Ann

Skinner

Wife
Female

Mary A

Skinner

Daughter
Male

James W W

Skinner

Son
Male

Aaron J

Skinner

Son
Female

Ann

Skinner

Daughter
Male

John

Skinner

Nephew
Male

William

Parkins

Boarder
First name(s) James
Last name Skinner
Relationship Head
Marital status Married
Age 46
Birth year 1835
Birth place -

Household members (8 people)

First name(s)

Last name

Relationship

Marital status

Age

Birth year

Birth place

Full record

James

Skinner

Head

Married

46

1835

-

Ann

Skinner

Wife

Married

45

1836

Cambridge, Cambridgeshire, England

Mary A

Skinner

Daughter

Single

18

1863

Paddington, Middlesex, England

James W W

Skinner

Son

Single

11

1870

Paddington, Middlesex, England

Aaron J

Skinner

Son

Single

6

1875

Paddington, Middlesex, England

Ann

Skinner

Daughter

Single

2

1879

Paddington, Middlesex, England

John

Skinner

Nephew

Single

22

1859

Mayfair, Middlesex, England

William

Parkins

Boarder

Single

20

1861

Landore, Glamorganshire, Wales

Explore Findmypast's newspaper collections

Explore the 1881 Census and millions of historical records for free with Findmypast. Find out more about the household of James Skinner in Kensington in 1881, and follow the Skinner family through time in other national records, newspapers and more.

We've found family trees for James Skinner

We’ve found James Skinner in 324 family trees. Find out more about James Skinner's household and view the Skinner family in family trees created by Findmypast members.

Not who you're looking for?