Skip to content
  • Start free trial
An original census record

Start a free trial to view

Get access to the original record, as well as a map showing the local area at the time

Household of Harry Lee Butterworth (born 1844, Lancashire)

1881 England, Wales & Scotland Census in Rochdale, Lancashire, England

Harry Lee Butterworth and 5 other people are on this record


Get access to the original record, as well as a map showing the local area at the time

Harry Lee Butterworth's household

Male

Harry Lee

Butterworth

Head
Female

Jane

Butterworth

Wife
Female

Mary Eliz

Butterworth

Daughter
Female

Ada Jane

Butterworth

Daughter
Male

Harry Lee

Butterworth

Son
Female

Bertha Al

Butterworth

Daughter
First name(s) Harry Lee
Last name Butterworth
Relationship Head
Marital status Married
Age 37
Birth year 1844
Birth place Rochdale, Lancashire, England

Household members (6 people)

First name(s)

Last name

Relationship

Marital status

Age

Birth year

Birth place

Full record

Harry Lee

Butterworth

Head

Married

37

1844

Rochdale, Lancashire, England

Jane

Butterworth

Wife

Married

37

1844

Rochdale, Lancashire, England

Mary Eliz

Butterworth

Daughter

Single

15

1866

Rochdale, Lancashire, England

Ada Jane

Butterworth

Daughter

Single

5

1876

Rochdale, Lancashire, England

Harry Lee

Butterworth

Son

Single

3

1878

Rochdale, Lancashire, England

Bertha Al

Butterworth

Daughter

Single

0

1881

Rochdale, Lancashire, England

Explore Findmypast's newspaper collections

Explore the 1881 Census and millions of historical records for free with Findmypast. Find out more about the household of Harry Lee Butterworth in Rochdale in 1881, and follow the Butterworth family through time in other national records, newspapers and more.

We've found family trees for Harry Lee Butterworth

We’ve found Harry Lee Butterworth in 3 family trees. Find out more about Harry Lee Butterworth's household and view the Butterworth family in family trees created by Findmypast members.

Not who you're looking for?